from dotty_dict import dotty
dot = dotty()
dot['very.deeply.nested.thing'] = 'spam'
dot
Dotty(dictionary={'very': {'deeply': {'nested': {'thing': 'spam'}}}}, separator='.', esc_char='\')

dot['very.deeply.spam'] = 'indeed'
dot
Dotty(dictionary={'very': {'deeply': {'nested': {'thing': 'spam'}, 'spam': 'indeed'}}}, separator='.', esc_char='\')

del dot['very.deeply.nested']
dot
Dotty(dictionary={'very': {'deeply': {'spam': 'indeed'}}}, separator='.', esc_char='\')

dot.get('very.not_existing.key')
None

NOTE: Using integer in dictionary keys will be treated as embedded list index.

Install for development

Install dev dependencies

.. code-block:: console

$ make install

Testing

.. code-block:: console

$ make test

Or full tests with TOX:

.. code-block:: console

$ make test-all

Limitations

In some very rare cases dotty may not work properly.

When nested dictionary has two keys of different type, but with the same value.
In that case dotty will return dict or list under random key with passed value.
Keys in dictionary may not contain dots. If you need to use dots, please specify dotty with custom separator.
Nested keys may not be bool type. Bool type keys are only supported when calling keys with type defined value (e.g. dot[True], dot[False]).

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dotty-dict

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